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5x^2-8.6x+3.6=0
a = 5; b = -8.6; c = +3.6;
Δ = b2-4ac
Δ = -8.62-4·5·3.6
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.6)-\sqrt{1.96}}{2*5}=\frac{8.6-\sqrt{1.96}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.6)+\sqrt{1.96}}{2*5}=\frac{8.6+\sqrt{1.96}}{10} $
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